CPI = (4x50 + 5x10 + 4x20 + 3x8 + 3x2)/100 = 3.6. 15 0 obj << /Type /XRef /Length 70 /Filter /FlateDecode /DecodeParms << /Columns 5 /Predictor 12 >> /W [ 1 3 1 ] /Index [ 12 45 ] /Info 10 0 R /Root 14 0 R /Size 57 /Prev 103597 /ID [<7ddedb40e1bd8c94dbf832faf764b4a3>] >> T{�����:��D�_��h�6�yA��į������� _����ҷ\��_���|�^��0�S@�|�Ny6(Mg+���Vf{����e2�nŏo�R����7�~�orD���I%�3��WE^7���Cfo��摌��,��U�����˺�NNV�Z������hc�G)%��+�-V@�̣U�e�v뀖: 7b�m�-*C�� Y�B>�"( �(1V �'�Mgӱ���Z^MW�U�`��FLl��" �YST���"���7\����X%M��UZ��W�)�J3/p�y5���K_�abayyb�"��B�b�Uy�*�:p�1��8eF �]W~�B �mU��,�Uv.w]�b�#'�|A��hҦ.i�����/��������j���Ze�BF^1*#�����n�1���"��}��w䕸���]�%?H���O��=FSFK�3��Gܺ��������?�}�{^��K�[p��! Find the clock cycles required in both cases. 1.4.2 [51 <1.4> What is the global CPI for each implementation? What is the global CPI for each implementation? << /Linearized 1 /L 103936 /H [ 901 174 ] /O 16 /E 75211 /N 4 /T 103596 >> class B, 50% class C, and 20% class D, which implementation is faster? endobj Calculation of CPI (Cycles Per Instruction) For the multi-cycle MIPS Load 5 cycles Store 4 cycles R-type 4 cycles Branch 3 cycles Jump 3 cycles If a program has 50% R-type instructions 10% load instructions 20% store instructions 8% branch instructions 2% jump instructions then what is the CPI?

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endstream endobj What is the global CPI for each implementation Find the clock cycles required from CDA 3103 at University of Central Florida The instructions can be divided into four classes according to their CPI (class A, B, C, and D). - 5th Edition.

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Do the calculation on your own, and check the, Speed up of new compiler compared to A = 1.67, Speed up of new compiler compared to B = 2.27, Performance is specific to a particular program, total execution time is a consistent summary of. �m�q�7��� �sI�W�u������2G�Chm� << /Filter /FlateDecode /Length 2004 >> �f_�ɪz^\#�����t t_ȋ�����9�K駷n�դ��x��!0XAAKa������U�dX��A�W���{�/g��Sb-���p�����A��pS��+��� �P��B�B * U��$+P�l) 4� p�@ rate and CPI of each implementation are given in the following table. Compilers can have a profound impact on the performance of an application. 14 0 obj %��������� c. Give two options for improving the CPU performance by 25%. instr.

compiler A or B on the original processor? 17 0 obj << /Pages 32 0 R /Type /Catalog >> Speedup = Old Execution Time = I old x CPI old x Clock cycle old New Execution Time I new x CPI new x Clock Cycle new Speedup = Old Execution Time = I old x CPI … 13 0 obj Community College of City University • AST 1020, Copyright © 2020.

program with 106 instructions divided into classes as follows: 10% class A, 20% class B, 50% class C, and 20% class D, which implementation is faster? CPI/clock rate Total time P1 = (105 + 2 10 5 2 + 5 10 3 + 2 105 3)=(2:5 109) = 10:4 10 4s Total time P2 = (105 52 + 2 105 52 + 5 10 2 + 2 10 2)=(3 109) = 6:66 10 4s Assume that for a program, compiler A results in a dynamic instruction count, of 1.0E9 and has an execution time of 1.1 s, while compiler B results in a. dynamic instruction count of 1.2E9 and an execution time of 1.5 s. Find the average CPI for each program given that the processor has a clock, Assume the compiled programs run on two different processors. << /Contents 17 0 R /MediaBox [ 0 0 612 792 ] /Parent 32 0 R /Resources 25 0 R /Type /Page >> x�[��������Հ�խ�H���ݵ ��f� ��B>L�Kn���TUW��#͘��.�]]u��ե���g�O���ݶ�iӗ��O�҇�n]zs���� ����n�"-ۼm�§7/��봖��r�"}x} ���7iv�J����_cB��vu�۴l��|��k�uk��2�|r,J�͛J�H�|$c>^���   Privacy P1 with a clock rate of 2.5 GHz and CPIs of 1, 2, 3, and 3, and P2 with a clock rate of 3 GHz and CPIs of 2, 2, 2, and 2. 16 0 obj a. 9����E� �����gC7 � This preview shows page 25 - 29 out of 29 pages. 12 0 obj << /Filter /FlateDecode /S 69 /Length 96 >> endobj

Assume that for a program, compiler A results in a dynamic instruction count of 1.0E9 and has an execution time of 1.1 s, while compiler B results in a dynamic instruction count of 1.2E9 and an execution time of 1.5 s. Time = No. Clock Rate: 2.0GHZ Class A: 20%, CPI 2 Class B: 30%, CPI 1 Class C: 10%, CPI 3 Class D: 20%, CPI 4 Class E: 20%, CPI 5 I solved a.b but not c .. so I need help- for problem c.. and here are the answer for the a and b . a) What is the global CPI for each implementation? What is the speedup of using this new compiler versus using. << /Length 5 0 R /Filter /FlateDecode >>

Class C : 5 105 instr. For a given architecture performance increases come from: increases in clock rate (without adverse CPI affects), improvements in processor organization that lower CPI, compiler enhancements that lower CPI and/or, : expecting improvement in one aspect of a, machine’s performance to affect the total performance, This textbook can be purchased at www.amazon.com. stream Course Hero is not sponsored or endorsed by any college or university. What is the global CPI for each implementation?

Speedup = (10,000,000 x 2.5 x 5x10-9) / (9,500,000 x 3 x 3.33x10-9 ) = .125 / .095 = 1.32 or 32 % faster after changes. Given a .

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This problem will explore the impact compilers have on execution time.

stream What's the global CPI?   Terms. stream %���� Class B : 2 X 105 instr. What is the global CPI for each implementation Find the clock cycles required.

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stream For a limited time, find answers and explanations to over 1.2 million textbook exercises for FREE! Course Hero, Inc. 4 0 obj Clockrate CPI ClassA CPI ClassB CPI ClassC CPI Class D 1.5 GHz 2 GHz 1.4.1 [10] <1.4> Given a program with 106 instructions divided into classes as follows: 10% class A, 20% class B, 50% class C and 20% class D, which implemen- tation is faster?

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Get step-by-step explanations, verified by experts. Class A : 105 instr. ��i�^T��$�eB#FY�nj8Q&Qo�����Y���WYf�h��Ld��JPS�N�IV�eU#���]p������ {D�%( �e�p!����M���̬k��K2z���S��ŒI2��K��L�V�����Ț��i�0�Rf�/Z�u�6�y��}a����q �i�Z����?����7 � 4������#X��~譼:{T��ك�_Z���*ʼp)��|��xAa�ɯ�R���UɻJ�,/��%�!y��/� 8Χ@ A���T�z�^��6 4�#%9�{*/� �+�\�s+�X��:�$�@s��ylF a.

3. If the execution, times on the two processors are the same, how much faster is the clock of the, processor running compiler A’s code versus the clock of the processor running, A new compiler is developed that uses only 6.0E8 instructions and has an, average CPI of 1.1. �b�˯�Y�`��_5��Z��ijd_o*����2�0oE��z(Y�lR��n&�������P�n$�u�d:G�j�!�@��7g��D���D)����\���HF�$�2ϢiG��!�K����؞�:T�(��4�x�a&o9�5����|\��F�S�b(ɮF��u6�h#��q~����8t��9�r[��4U����~�1�D�О�#��ܜ��̹�44� O���5fj�)��� � 3�;%���W�-Ww������S�َ瀘��/�/ے�����x�F&�h ����L�آ߭)W�!o�PWz'w�E�5jã�� H�b���ۅ�_,wyM� ���. b) Find the clock cycles required in both cases. [10 pts] b) What is the global CPI for each implementation? *Wc*NM�B߿04�2�. Computer Organization and Design MIPS Edition: The Hardware/Software Interface

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[5 pts] 15) Compilers can have a profound impact on the performance of an application on a given processor. New CPI: 3.0 – Faster CPU implementation: New clock rate = 300 MHz • What is the speedup with the changes?

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